If it's not what You are looking for type in the equation solver your own equation and let us solve it.
0=-0.12x^2+3x
We move all terms to the left:
0-(-0.12x^2+3x)=0
We add all the numbers together, and all the variables
-(-0.12x^2+3x)=0
We get rid of parentheses
0.12x^2-3x=0
a = 0.12; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·0.12·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*0.12}=\frac{0}{0.24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*0.12}=\frac{6}{0.24} =25 $
| x-(x/3+1)=327 | | 4(8)-16+x=25 | | 2x+5/6=-20 | | 8(c-3)=4c+9c-14 | | 8+5=10x | | 11x-2=75+2 | | q0q=q^-4 | | x-3x+1=327 | | -4x+57=-13x+20 | | 45(p)=60 | | x/3+1=327 | | 6x-0.02=11.98 | | (2x+65)=40+(9x-45) | | x-x/3+1=327 | | (2/5x)+(1/6)=-4 | | 21x-1=11x+1 | | 11=33•b | | 9+1/2x=15 | | 1/5*y+11=3-3/5*y | | 2x+4(-7-2x)=-5 | | Y/2(y-5)=2y+2 | | 7-2y=y+16 | | 2y+2=y+2(y-5) | | -9y=20y | | 14^9x=11^-6-x | | 7m^2+4=m | | -x^2/48+4x=0 | | +5/8x=-10 | | 3(b−13)−-1=16 | | -12=-2(k-4) | | -9y=20 | | -5(8v+4)=-6(6+4v) |